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13. Roman to Integer

Roman numerals are represented by seven different symbols: I, V, X, L, C, D and M.

Symbol       Value
I             1
V             5
X             10
L             50
C             100
D             500
M             1000

For example, two is written as II in Roman numeral, just two one’s added together. Twelve is written as, XII, which is simply X + II. The number twenty seven is written as XXVII, which is XX + V + II.

Roman numerals are usually written largest to smallest from left to right. However, the numeral for four is not IIII. Instead, the number four is written as IV. Because the one is before the five we subtract it making four. The same principle applies to the number nine, which is written as IX. There are six instances where subtraction is used:

  • I can be placed before V (5) and X (10) to make 4 and 9.

  • X can be placed before L (50) and C (100) to make 40 and 90.

  • C can be placed before D (500) and M (1000) to make 400 and 900.

Given a roman numeral, convert it to an integer. Input is guaranteed to be within the range from 1 to 3999.

Example 1:

Input: "III"
Output: 3

Example 2:

Input: "IV"
Output: 4

Example 3:

Input: "IX"
Output: 9

Example 4:

Input: "LVIII"
Output: 58
Explanation: L = 50, V= 5, III = 3.

Example 5:

Input: "MCMXCIV"
Output: 1994
Explanation: M = 1000, CM = 900, XC = 90 and IV = 4.

解题分析

查看罗马数字,如果左边的数字比右边大,则就是需要做减法,否则做加法。

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/**
 * 从右向左,从小到大,更容易理解
 *
 * @author D瓜哥 · https://www.diguage.com
 * @since 2019-07-11 17:14
 */
public int romanToInt(String s) {
  int result = 0;
  int pre = 0;
  for (int i = s.length() - 1; i >= 0; i--) {
    int curr = charToNum(s.charAt(i));
    if (curr >= pre) {
      result += curr;
    } else {
      result -= curr;
    }
    pre = curr;
  }
  return result;
}

private int charToNum(char c) {
  switch (c) {
    case 'I': return 1;
    case 'V': return 5;
    case 'X': return 10;
    case 'L': return 50;
    case 'C': return 100;
    case 'D': return 500;
    case 'M': return 1000;
    default: return 0;
  }
}

// 从左向右处理
public int romanToIntLeftToRight(String s) {
  int result = 0;
  int prenum = charToNum(s.charAt(0));
  for (int i = 1; i < s.length(); i++) {
    int num = charToNum(s.charAt(i));
    if (prenum < num) {
      result -= prenum;
    } else {
      result += prenum;
    }
    prenum = num;
  }
  result += prenum;
  return result;
}

public int romanToInt2(String s) {
  int result = 0;
  if (Objects.isNull(s) || s.length() == 0) {
    return result;
  }

  HashMap<String, Integer> r2i = new HashMap<>();
  r2i.put("I", 1);
  r2i.put("V", 5);
  r2i.put("X", 10);
  r2i.put("L", 50);
  r2i.put("C", 100);
  r2i.put("D", 500);
  r2i.put("M", 1000);
  r2i.put("IV", 4);
  r2i.put("IX", 9);
  r2i.put("XL", 40);
  r2i.put("XC", 90);
  r2i.put("CD", 400);
  r2i.put("CM", 900);

  for (int i = s.length(); i > 0; ) {
    int step = 2;
    int beginIndex = i - step;
    if (beginIndex < 0) {
      beginIndex = 0;
    }
    String symbol = s.substring(beginIndex, i);
    Integer value = r2i.get(symbol);
    if (Objects.isNull(value)) {
      step = 1;
      beginIndex = i - step;
      if (beginIndex < 0) {
        beginIndex = 0;
      }
      symbol = s.substring(beginIndex, i);
      value = r2i.get(symbol);
    }
    result += value;
    i -= step;
  }
  return result;
}