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406. Queue Reconstruction by Height
Suppose you have a random list of people standing in a queue. Each person is described by a pair of integers (h, k), where h is the height of the person and k is the number of people in front of this person who have a height greater than or equal to h. Write an algorithm to reconstruct the queue.
Note:
The number of people is less than 1,100.
Input:
[[7,0], [4,4], [7,1], [5,0], [6,1], [5,2]]
Output:
[[5,0], [7,0], [5,2], [6,1], [4,4], [7,1]]这道题有点不明觉厉。
参考资料
Suppose you have a random list of people standing in a queue. Each person is described by a pair of integers (h, k), where h is the height of the person and k is the number of people in front of this person who have a height greater than or equal to h. Write an algorithm to reconstruct the queue.
Note:
The number of people is less than 1,100.
Example
Input:
[[7,0], [4,4], [7,1], [5,0], [6,1], [5,2]]
Output:
[[5,0], [7,0], [5,2], [6,1], [4,4], [7,1]] 1
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/**
* Runtime: 8 ms, faster than 39.43% of Java online submissions for Queue Reconstruction by Height.
* Memory Usage: 42.6 MB, less than 89.36% of Java online submissions for Queue Reconstruction by Height.
*
* @author D瓜哥 · https://www.diguage.com
* @since 2020-01-29 17:20
*/
public int[][] reconstructQueue(int[][] people) {
Arrays.sort(people, (a, b) -> a[0] == b[0] ? a[1] - b[1] : b[0] - a[0]);
List<int[]> queue = new LinkedList<>();
for (int[] person : people) {
queue.add(person[1], person);
}
int length = people.length;
return queue.toArray(new int[length][2]);
}