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148. Sort List
Sort a linked list in O(n log n) time using constant space complexity.
Example 1:
Input: 4->2->1->3 Output: 1->2->3->4
Example 2:
Input: -1->5->3->4->0 Output: -1->0->3->4->5
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/**
* Runtime: 4 ms, faster than 62.99% of Java online submissions for Sort List.
*
* Memory Usage: 40.2 MB, less than 89.47% of Java online submissions for Sort List.
*/
public ListNode sortList(ListNode head) {
if (Objects.isNull(head) || Objects.isNull(head.next)) {
return head;
}
ListNode prev = null;
ListNode slow = head;
ListNode fast = head;
while (Objects.nonNull(fast) && Objects.nonNull(fast.next)) {
prev = slow;
slow = slow.next;
fast = fast.next.next;
}
prev.next = null;
ListNode firstResult = sortList(head);
ListNode secondResult = sortList(slow);
return merge(firstResult, secondResult);
}
private ListNode merge(ListNode first, ListNode second) {
ListNode result = new ListNode(0);
ListNode tail = result;
while (Objects.nonNull(first) && Objects.nonNull(second)) {
if (first.val < second.val) {
tail.next = first;
first = first.next;
} else {
tail.next = second;
second = second.next;
}
tail = tail.next;
}
if (Objects.isNull(first)) {
tail.next = second;
}
if (Objects.isNull(second)) {
tail.next = first;
}
return result.next;
}