友情支持
如果您觉得这个笔记对您有所帮助，看在D瓜哥码这么多字的辛苦上，请友情支持一下，D瓜哥感激不尽，😜
|
|
有些打赏的朋友希望可以加个好友，欢迎关注D 瓜哥的微信公众号，这样就可以通过公众号的回复直接给我发信息。
公众号的微信号是: jikerizhi。因为众所周知的原因，有时图片加载不出来。 如果图片加载不出来可以直接通过搜索微信号来查找我的公众号。 |
744. Find Smallest Letter Greater Than Target
Given a list of sorted characters letters containing only lowercase letters, and given a target letter target, find the smallest element in the list that is larger than the given target.
Letters also wrap around. For example, if the target is target = 'z' and letters = ['a', 'b'], the answer is 'a'.
Examples:
Input:
letters = ["c", "f", "j"]
target = "a"
Output: "c"
Input:
letters = ["c", "f", "j"]
target = "c"
Output: "f"
Input:
letters = ["c", "f", "j"]
target = "d"
Output: "f"
Input:
letters = ["c", "f", "j"]
target = "g"
Output: "j"
Input:
letters = ["c", "f", "j"]
target = "j"
Output: "c"
Input:
letters = ["c", "f", "j"]
target = "k"
Output: "c"Note:
-
lettershas a length in range[2, 10000]. -
lettersconsists of lowercase letters, and contains at least 2 unique letters. -
targetis a lowercase letter.
-
一刷
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
/**
* @author D瓜哥 · https://www.diguage.com
* @since 2024-08-23 17:04:36
*/
public char nextGreatestLetter(char[] letters, char target) {
int length = letters.length;
if (target >= letters[length - 1]) {
return letters[0];
}
int left = 0, right = length - 1;
while (left < right) {
int mid = left + (right - left) / 2;
if (target < letters[mid]) {
right = mid;
} else {
left = mid + 1;
}
}
return letters[left];
}