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56. Merge Intervals
Given a collection of intervals, merge all overlapping intervals.
Example 1:
Input: [[1,3],[2,6],[8,10],[15,18]] Output: [[1,6],[8,10],[15,18]] Explanation: Since intervals [1,3] and [2,6] overlaps, merge them into [1,6].
Example 2:
Input: [[1,4],[4,5]] Output: [[1,5]] Explanation: Intervals [1,4] and [4,5] are considered overlapping.
NOTE: input types have been changed on April 15, 2019. Please reset to default code definition to get new method signature.
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/**
* @author D瓜哥 · https://www.diguage.com
* @since 2019-10-23 12:27
*/
public int[][] merge(int[][] intervals) {
if (Objects.isNull(intervals) || intervals.length <= 1) {
return intervals;
}
Arrays.sort(intervals, Comparator.comparingInt(o -> o[0]));
int index = 0;
for (int i = 1; i < intervals.length; i++) {
if (index < 0 || intervals[index][1] < intervals[i][0]) {
intervals[index + 1] = intervals[i];
index++;
} else {
intervals[index][1] = Math.max(intervals[i][1], intervals[index][1]);
}
}
return Arrays.copyOf(intervals, index + 1);
}