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530. Minimum Absolute Difference in BST
Given a binary search tree with non-negative values, find the minimum absolute difference between values of any two nodes.
Example:
Input:
1
\
3
/
2
Output:
1
Explanation:
The minimum absolute difference is 1, which is the difference between 2 and 1 (or between 2 and 3).Note: There are at least two nodes in this BST.
思路分析
看到二叉搜索树，就要想到中序遍历。
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public int getMinimumDifference(TreeNode root) {
int result = Integer.MAX_VALUE;
TreeNode cur = root;
TreeNode mostRight;
TreeNode pre = null;
while (cur != null) {
mostRight = cur.left;
if (mostRight != null) {
while (mostRight.right != null && mostRight.right != cur) {
mostRight = mostRight.right;
}
if (mostRight.right == null) {
mostRight.right = cur;
cur = cur.left;
continue;
} else {
mostRight.right = null;
}
}
if (pre != null) {
result = Math.min(result, cur.val - pre.val);
}
pre = cur;
cur = cur.right;
}
return result;
}