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1823. Find the Winner of the Circular Game
There are n
friends that are playing a game. The friends are sitting in a circle and are numbered from 1
to n
in clockwise order. More formally, moving clockwise from the ith
friend brings you to the (i+1)th
friend for 1 ⇐ i < n
, and moving clockwise from the nth
friend brings you to the 1st
friend.
The rules of the game are as follows:
-
Start at the
1st
friend. -
Count the next
k
friends in the clockwise direction including the friend you started at. The counting wraps around the circle and may count some friends more than once. -
The last friend you counted leaves the circle and loses the game.
-
If there is still more than one friend in the circle, go back to step
2
starting from the friend immediately clockwise of the friend who just lost and repeat. -
Else, the last friend in the circle wins the game.
Given the number of friends, n
, and an integer k
, return the winner of the game.
Example 1:
Input: n = 5, k = 2
Output: 3
Explanation: Here are the steps of the game:
1) Start at friend 1.
2) Count 2 friends clockwise, which are friends 1 and 2.
3) Friend 2 leaves the circle. Next start is friend 3.
4) Count 2 friends clockwise, which are friends 3 and 4.
5) Friend 4 leaves the circle. Next start is friend 5.
6) Count 2 friends clockwise, which are friends 5 and 1.
7) Friend 1 leaves the circle. Next start is friend 3.
8) Count 2 friends clockwise, which are friends 3 and 5.
9) Friend 5 leaves the circle. Only friend 3 is left, so they are the winner.
Example 2:
Input: n = 6, k = 5
Output: 1
Explanation: The friends leave in this order: 5, 4, 6, 2, 3. The winner is friend 1.
Constraints:
-
1 <= k <= n <= 500
Follow up:
Could you solve this problem in linear time with constant space?
思路分析
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/**
* @author D瓜哥 · https://www.diguage.com
* @since 2024-09-19 15:24:45
*/
public int findTheWinner(int n, int k) {
Queue<Integer> queue = new ArrayDeque<>(n);
for (int i = 1;i<=n;i++) {
queue.offer(i);
}
while(queue.size()>1) {
for (int i= 1;i<k;i++) {
queue.offer(queue.poll());
}
queue.poll();
}
return queue.poll();
}