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206. Reverse Linked List

递归需要加强一下,反转链表的递归细节再推敲推敲。

Reverse a singly linked list.

Example:

Input: 1->2->3->4->5->NULL
Output: 5->4->3->2->1->NULL

Follow up:

A linked list can be reversed either iteratively or recursively. Could you implement both?

思路分析

0206 01
  • 一刷

  • 二刷

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/**
 * Runtime: 0 ms, faster than 100.00% of Java online submissions for Reverse Linked List.
 *
 * Memory Usage: 38 MB, less than 6.48% of Java online submissions for Reverse Linked List.
 *
 * @author D瓜哥 · https://www.diguage.com
 * @since 2020-01-12 12:47
 */
public ListNode reverseList(ListNode head) {
  if (head == null || head.next == null) {
    return head;
  }
  ListNode curr = null;
  while (head != null) {
    ListNode next = head.next;
    head.next = curr;
    curr = head;
    head = next;
  }
  return curr;
}

/**
 * Runtime: 0 ms, faster than 100.00% of Java online submissions for Reverse Linked List.
 *
 * Memory Usage: 37.8 MB, less than 51.44% of Java online submissions for Reverse Linked List.
 */
public ListNode reverseListRecursion(ListNode head) {
    if (Objects.isNull(head) || Objects.isNull(head.next)) {
        return head;
    }
    // 这个反转地方,还要再仔细推敲一下!!
    ListNode node = reverseListRecursion(head.next);
    head.next.next = head;
    head.next = null;
    return node;
}
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/**
 * @author D瓜哥 · https://www.diguage.com
 * @since 2024-09-13 16:24:00
 */
public ListNode reverseList(ListNode head) {
  return reverseList(head, null);
}

public ListNode reverseList(ListNode head, ListNode pre) {
  if (head == null) {
    return pre;
  }
  ListNode result = reverseList(head.next, head);
  head.next = pre;
  return result;
}

思考题

可以尝试一下递归!

另外,思考一下如何通过传参来简化代码。